If a solid object with a density greater than that of water is submerged to a depth of 10 meters, calculate the net buoyant force acting on it when the hydrostatic pressure is also considered. What is the net effect if the object is released from that depth?

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Seekh · Accepted Answer

The buoyant force equals the weight of the water displaced, so it is ρwater V g, independent of how deep the object is. The hydrostatic pressure increases with depth, but the pressure on the bottom of the object is higher than on the top, and the difference exactly equals the buoyant force, leaving no extra effect. Thus the net buoyant force at 10 m is still ρwater V g, the same as at the surface. Because the object's density is higher than water, its weight exceeds this buoyant force, so it will sink if released. For example, a 0.

If a solid object with a density greater than that of water is submerged to a depth of 10 meters, calculate the net buoyant force acting on it when the hydrostatic pressure is also considered. What is the net effect if the object is released from that depth?

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