Learning Path
Question & Answer1
Understand Question2
Review Options3
Learn Explanation4
Explore TopicChoose the Best Answer
A
196 N
B
200 N
C
210 N
D
250 N
Understanding the Answer
Let's break down why this is correct
Answer
The box’s weight is 50 kg, so its weight is 50 kg × 9. 8 m/s² ≈ 490 N, which is also the normal force pressing it onto the floor. Static friction can oppose a pulling force up to a maximum of μₛ × normal force. With a static‑friction coefficient μₛ = 0. 4, the largest force the floor can resist is 0.
Detailed Explanation
The maximum static friction force is found by multiplying the coefficient (0.4) by the normal force. Other options are incorrect because Choosing 200 N suggests using a rounded weight of 500 N instead of the exact 490 N; Selecting 210 N likely adds 10 N to the correct result, maybe thinking friction equals 0.42 instead of 0.4.
Key Concepts
Coefficient of Friction
Friction and Motion
Topic
Friction
Difficulty
medium level question
Cognitive Level
understand
Practice Similar Questions
Test your understanding with related questions
1
Question 1If a 10 kg box is resting on a flat surface with a coefficient of friction of 0.5, what is the maximum frictional force that can act on the box before it starts to slide?
easyPhysics
Practice
2
Question 2If you push a box across a floor and it doesn't move, what does this imply about the friction between the box and the floor?
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Practice
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