Learning Path
Question & Answer1
Understand Question2
Review Options3
Learn Explanation4
Explore TopicChoose the Best Answer
A
m g sin(α)
B
m g cos(α)
C
m g tan(α)
D
m g
Understanding the Answer
Let's break down why this is correct
Answer
The parallel component of gravity on an incline is found by projecting the weight onto the slope, giving \(mg\sin\alpha\). This comes from decomposing the weight vector \(mg\) into perpendicular and parallel parts relative to the plane. The perpendicular part is \(mg\cos\alpha\), while the remaining component pulls the block down the slope. For example, if a 5 kg block slides on a 30° incline, the downhill force is \(5\times9. 8\times\sin30^\circ \approx 24.
Detailed Explanation
Gravity pulls straight down toward the center of the Earth. Other options are incorrect because Some people think the push from the surface, called the normal force, also pulls the block down the slope; The tangent function tells how steep a slope is, not how much force pulls the block down.
Key Concepts
Gravitational Forces
Friction Forces
Inclined Planes
Topic
Friction Forces Analysis
Difficulty
medium level question
Cognitive Level
understand
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