Learning Path
Question & Answer1
Understand Question2
Review Options3
Learn Explanation4
Explore TopicChoose the Best Answer
A
Coefficient of sliding resistance
B
Coefficient of static resistance
C
Coefficient of air resistance
D
Coefficient of frictional dependence
Understanding the Answer
Let's break down why this is correct
Answer
Surface roughness determines how many microscopic bumps touch, which sets the coefficient of friction. Likewise, the amount of surface area that is in contact controls the frictional force that can be produced, because more area can transmit more shear stress. In other words, surface area is to friction force what roughness is to coefficient of friction. For example, a rougher shoe sole (higher μ) and a larger outsole area both increase the total friction that keeps you from slipping. Thus, surface area plays the same role for friction force as roughness does for the coefficient.
Detailed Explanation
Sliding resistance coefficient describes how much force is needed to keep two surfaces sliding. Other options are incorrect because Static resistance refers to the force needed to start movement; Air resistance acts on objects moving through air.
Key Concepts
Friction Coefficient Variations
Surface Properties
Inclined Motion
Topic
Friction Coefficient Variations
Difficulty
easy level question
Cognitive Level
understand
Practice Similar Questions
Test your understanding with related questions
1
Question 1How does surface roughness influence the frictional interaction between two materials?
easyPhysics
Practice
2
Question 2How does increasing surface roughness affect the friction coefficient between two sliding surfaces?
mediumPhysics
Practice
3
Question 3How does increasing the surface roughness of two sliding objects affect their friction coefficient on an incline?
hardPhysics
Practice
4
Question 4The friction coefficient is defined as the ratio of the frictional force to the ______ acting on an object.
easyPhysics
Practice
5
Question 5If the friction coefficient between two surfaces is 0.3, what does this imply about the forces involved?
easyPhysics
Practice
Ready to Master More Topics?
Join thousands of students using Seekh's interactive learning platform to excel in their studies with personalized practice and detailed explanations.