📚 Learning Guide
Friction Behavior Demonstration
medium

A 5 kg block is placed on a ramp inclined at an angle of 30 degrees. What is the maximum static frictional force that can act on the block if the coefficient of static friction between the block and the ramp is 0.4?

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Choose the Best Answer

A

7 N

B

10 N

C

20 N

D

5 N

Understanding the Answer

Let's break down why this is correct

Answer

The normal force on the block is the component of its weight perpendicular to the ramp: \(N = mg\cos30^\circ\). With \(m = 5\,\text{kg}\) and \(g = 9. 8\,\text{m/s}^2\), \(N = 5 \times 9. 8 \times 0. 866 \approx 42.

Detailed Explanation

The maximum static friction can only be as large as the product of the coefficient of static friction and the normal force. Other options are incorrect because This answer assumes the static friction could equal the entire parallel component of gravity, but friction can only reach the product of the coefficient and the normal force; Here the mistake is adding the normal and parallel forces together.

Key Concepts

Angle of Inclination
Normal Force
Topic

Friction Behavior Demonstration

Difficulty

medium level question

Cognitive Level

understand

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