If two charged objects, one with a charge of +3 µC and the other with a charge of -2 µC, are placed 0.5 meters apart, what will be the nature of the force acting between them according to Coulomb's Law?

According to Coulomb’s Law, the force between two point charges is \(F = k \frac{|q_1 q_2|}{r^2}\). Plugging in \(q_1 = +3\,\mu\text{C}\), \(q_2 = -2\,\mu\text{C}\) and \(r = 0. 5\text{ m}\) gives a positive magnitude of the force, but because the charges are opposite in sign, the force is attractive. The magnitude is \(F = 8. 99\times10^9 \frac{(3\times10^{-6})(2\times10^{-6})}{(0.