Learning Path
Question & Answer1
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Explore TopicChoose the Best Answer
A
The induced charge increases, leading to a stronger electric field between the plates.
B
The induced charge decreases, resulting in a weaker electric field.
C
The induced charge remains the same, but the direction of the electric field reverses.
D
The induced charge redistributes itself, but the overall electric field remains unchanged.
Understanding the Answer
Let's break down why this is correct
Answer
When a dielectric is inserted between the plates, the external field makes the molecules inside the dielectric align, creating bound surface charges on the dielectric’s inner surfaces. These bound charges act like a secondary set of plates, producing their own electric field that opposes the original field. As a result the free charge that the plates must supply is reduced; the magnitude of the free charge on each plate is smaller by a factor of the dielectric constant, so the induced charge distribution on the plates is less intense. For example, if a vacuum capacitor has a charge \(Q\), inserting a dielectric with \(\varepsilon_r = 4\) will reduce the plate charge to \(Q/4\) while the bound charges inside the dielectric carry the remaining field. Thus, the plates’ induced charge distribution becomes weaker and partially counterbalanced by the dielectric’s own polarization.
Detailed Explanation
When the dielectric is polarized, the dipoles inside arrange with negative ends toward the positive plate and positive ends toward the negative plate. Other options are incorrect because The misconception is that polarization pulls charge away, reducing the field; It is wrong to think the charge stays the same and the field reverses.
Key Concepts
Polarization of Dielectrics
Induced Charge Distribution
Topic
Electric Field Induction Extension
Difficulty
medium level question
Cognitive Level
understand
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Question 1In a parallel plate capacitor filled with a dielectric material, if the dielectric constant of the material is doubled, how will this affect the capacitance and the electric field between the plates when the charge remains constant?
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Question 2A technician is designing a capacitor using an insulating material as the dielectric. When an external electric field is applied to the capacitor, the technician observes that the dielectric material becomes polarized. How does this polarization affect the electric field within the capacitor?
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Question 3How does inserting a dielectric material into a capacitor affect the charge on its plates?
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Question 4When a dielectric material is inserted into a capacitor, what is the primary effect on the electric field within the capacitor?
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