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Answer
An ideal operational amplifier produces an output that equals the difference between its two input voltages multiplied by its open‑loop gain, so the basic relationship is \(V_{out}=A_{ol}(V_{+}-V_{-})\). In practice, the gain is finite and the amplifier has limits such as supply voltage, input bias current, offset voltage, bandwidth, and slew‑rate, so the output may saturate or distort at high frequencies or large input differences. For example, if a 10‑gain op‑amp has \(V_{+}=1. 0\text{ V}\) and \(V_{-}=0. 5\text{ V}\), the ideal output would be \(5\text{ V}\), but if the supply rails are ±5 V the amplifier will clamp at the rails and the real output might be slightly lower.
Detailed Explanation
An op‑amp does amplify the voltage difference between its inputs, but the amount it multiplies by (the gain) depends on how the circuit is set up. Other options are incorrect because Some people think the op‑amp always gives the same multiplied output.
Key Concepts
Operational Amplifier Functionality
Gain Variation in Op-Amps
Feedback in Op-Amps
Topic
Operational Amplifiers Basics
Difficulty
easy level question
Cognitive Level
understand
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