Learning Path
Question & Answer1
Understand Question2
Review Options3
Learn Explanation4
Explore TopicChoose the Best Answer
A
To stabilize the gain and improve linearity
B
To increase the output voltage
C
To decrease the input current
D
To eliminate noise completely
Understanding the Answer
Let's break down why this is correct
Answer
In a negative‑feedback op‑amp, the main reason to add feedback is to make the amplifier behave predictably and linearly, rather than letting its internal transistor variations dictate the output. The feedback forces the amplifier’s input and output to satisfy a simple equation that depends only on external resistors, giving a stable, known gain. This stabilizes the gain, reduces distortion, and limits the effect of temperature or device‑to‑device differences. As a result, the circuit’s behavior is determined by the chosen resistor values, not by the op‑amp’s internal parameters. For example, connecting a resistor from the output to the inverting input forces the op‑amp to adjust its output until the voltage difference at the inputs is zero, ensuring a precise 10× gain.
Detailed Explanation
Negative feedback reduces the difference between the desired output and the actual output. Other options are incorrect because Many think feedback boosts output voltage, but it actually limits it; Students may think feedback reduces input current, but it mainly controls voltage.
Key Concepts
Op-Amp Gain
Negative Feedback
Circuit Stability
Topic
Op-Amp Gain and Practical Considerations
Difficulty
easy level question
Cognitive Level
understand
Practice Similar Questions
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Question 2An engineer is designing a circuit using an operational amplifier and decides to implement negative feedback. Which of the following scenarios best illustrates the concept of negative feedback in op-amps?
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Question 3When an operational amplifier (op-amp) is configured with negative feedback, what is the primary effect observed at the output?
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Question 4In a negative feedback configuration using an op-amp, what is the primary effect on the output voltage when the input voltage increases?
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