Learning Path
Question & Answer1
Understand Question2
Review Options3
Learn Explanation4
Explore TopicChoose the Best Answer
A
High shear forces with a rubbery copolymer and a crystalline thermoplastic
B
Low cooling rates with two amorphous polymers
C
Moderate temperatures with a thermoplastic elastomer and a rigid polymer
D
Rapid cooling with two crystalline polymers
Understanding the Answer
Let's break down why this is correct
Answer
Blending a rigid polymer such as polycarbonate with a rubbery component like SEBS (styrene‑ethylene‑butylene‑styrene) and adding a small amount of a compatibilizer (e. g. , a block copolymer) creates a phase‑separated microstructure that dissipates impact energy. Processing the blend at a temperature above both polymers’ melting points (around 260 °C) and then cooling slowly allows the two phases to grow to an optimal size—too small and the rubber is ineffective, too large and the blend becomes brittle. The resulting interpenetrating network gives high toughness while maintaining stiffness.
Detailed Explanation
High shear forces stir the mix quickly, which forces a rubbery copolymer to break into tiny droplets. Other options are incorrect because Low cooling rates keep the two amorphous polymers mixed together for a long time; Moderate temperatures give the polymers some movement, but they are not forced to separate.
Key Concepts
Polymer Blends and Copolymers
Effect of Processing Conditions on Morphology
Phase Separation
Topic
Polymer Morphology
Difficulty
hard level question
Cognitive Level
understand
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