📚 Learning Guide
Bomb Calorimetry
hard

In a bomb calorimeter experiment, a sample with a mass of 2 grams is combusted, resulting in a temperature increase of 15°C. If the heat capacity of the calorimeter is known to be 4.5 kJ/°C, what is the total heat released during the combustion process, assuming thermal equilibrium is reached?

Master this concept with our detailed explanation and step-by-step learning approach

Learning Path
Learning Path

Question & Answer
1
Understand Question
2
Review Options
3
Learn Explanation
4
Explore Topic

Choose the Best Answer

A

5 kJ

B

30 kJ

C

60 kJ

D

90 kJ

Understanding the Answer

Let's break down why this is correct

Answer

The heat released by the sample is calculated by multiplying the calorimeter’s heat capacity by the temperature rise. The calorimeter’s heat capacity is 4. 5 kJ/°C, and the temperature increase is 15 °C. Multiplying gives 4. 5 kJ/°C × 15 °C = 67.

Detailed Explanation

The heat capacity tells how much heat the calorimeter takes to rise one degree Celsius. Other options are incorrect because Many students think the temperature rise should be multiplied by the calorimeter’s capacity, giving 67.5 kJ, then they mis‑read that as 30 kJ; Some students assume the heat capacity is per gram, so they divide 67.5 kJ by 2 grams, arriving at 60 kJ.

Key Concepts

Thermal Equilibrium
Calorimeter Design
Bomb Calorimetry Equation
Topic

Bomb Calorimetry

Difficulty

hard level question

Cognitive Level

understand

Ready to Master More Topics?

Join thousands of students using Seekh's interactive learning platform to excel in their studies with personalized practice and detailed explanations.