If two charged objects, one with a charge of +3 µC and the other with a charge of -2 µC, are placed 0.5 meters apart, what will be the nature of the force acting between them according to Coulomb's Law?

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Seekh · Accepted Answer

According to Coulomb’s Law, the force between two point charges is $F = k \frac{|q_1 q_2|}{r^2}$. Plugging in $q_1 = +3\,\mu\text{C}$, $q_2 = -2\,\mu\text{C}$ and $r = 0. 5\text{ m}$ gives a positive magnitude of the force, but because the charges are opposite in sign, the force is attractive. The magnitude is \(F = 8. 99\times10^9 \frac{(3\times10^{-6})(2\times10^{-6})}{(0.

If two charged objects, one with a charge of +3 µC and the other with a charge of -2 µC, are placed 0.5 meters apart, what will be the nature of the force acting between them according to Coulomb's Law?

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